Posted by **dd** on Friday, April 12, 2013 at 12:11am.

Consider a circuit with an RL series with L=0.09 H and R=0.05 Ohm. At t=0 the circuit is connected to a battery which provides V0=12 V.

(a)How long does it take to the current to equal a fraction 0.95 of the steady state current?

(b) What is the energy stored (in Joules) in the magnetic field when the current equals a fraction 0.95 of the steady state current?

(c) What is the total energy delivered (in Joules) by the battery up to the time t found in part (a) ?

How much energy (in Joules) has been dissipated in the resistor?

- physSteady-state current.ics -
**Henry **, Sunday, April 14, 2013 at 2:09pm
b. I = E/R = 12/0.05 = 240A, =

- physics -
**Henry **, Sunday, April 14, 2013 at 3:35pm
Please ignore my 1st response. My

computer malfunctioned. I will have to

repeat the entire process.

- physics -
**Henry **, Sunday, April 14, 2013 at 3:55pm
a. I = E/R = 12/0.05 = 240A.

0.95I = 0.95*240 = 228A.

Vr + Vc = 12

228*0.05 + 12/e^(t/T) = 12

11.4 + 12/e^(t/T) = 12

12/e^(t/T) = 12-11.4 = 0.6

e^(t/T) = 12/0.6 = 20

t/T = 3.

T = L/R = 0.09/0.05 = 1.8=Time constant.

t/1.8 = 3

t = 5.4 s.

b. Energy = 0.5L*I^2=.5*0.09*(228)^2 =

2339.3 J.

- physics -
**dd**, Monday, April 15, 2013 at 2:04am
thanks, do you have the c?

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