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physics

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Consider a circuit with an RL series with L=0.09 H and R=0.05 Ohm. At t=0 the circuit is connected to a battery which provides V0=12 V.

(a)How long does it take to the current to equal a fraction 0.95 of the steady state current?

(b) What is the energy stored (in Joules) in the magnetic field when the current equals a fraction 0.95 of the steady state current?

(c) What is the total energy delivered (in Joules) by the battery up to the time t found in part (a) ?

How much energy (in Joules) has been dissipated in the resistor?

  • physSteady-state current.ics - ,

    b. I = E/R = 12/0.05 = 240A, =

  • physics - ,

    Please ignore my 1st response. My
    computer malfunctioned. I will have to
    repeat the entire process.

  • physics - ,

    a. I = E/R = 12/0.05 = 240A.
    0.95I = 0.95*240 = 228A.
    Vr + Vc = 12
    228*0.05 + 12/e^(t/T) = 12
    11.4 + 12/e^(t/T) = 12
    12/e^(t/T) = 12-11.4 = 0.6
    e^(t/T) = 12/0.6 = 20
    t/T = 3.
    T = L/R = 0.09/0.05 = 1.8=Time constant.
    t/1.8 = 3
    t = 5.4 s.

    b. Energy = 0.5L*I^2=.5*0.09*(228)^2 =
    2339.3 J.

  • physics - ,

    thanks, do you have the c?

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