calculate the concentration of all ions present in 58.7 mg NH4Br in 500 mL of solution

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To calculate the concentration of all ions present in the solution, we first need to find the number of moles of NH4Br in the 58.7 mg sample. Then, we can use this information to determine the concentration.

Step 1: Calculate the number of moles of NH4Br
The molar mass of NH4Br can be found by summing the atomic masses of its constituent elements:
NH4Br = (1 x 14.01) + (4 x 1.01) + 79.90 = 97.05 g/mol

Now, we can calculate the number of moles of NH4Br in the sample:
mass (g) = mass (mg) / 1000 = 58.7 / 1000 = 0.0587 g

moles of NH4Br = mass (g) / molar mass (g/mol) = 0.0587 / 97.05 = 0.000604 mol

Step 2: Calculate the concentration of all ions

Since NH4Br dissociates into NH4+ and Br- ions in water, the concentration of each ion will be the same as the total concentration of NH4Br because of a 1:1 mole ratio.

Concentration (mol/L) = moles of solute / volume of solution (L)

Given that the volume of the solution is 500 mL, or 0.5 L, we can calculate the concentrations:

Concentration of NH4+ ion = Concentration of Br- ion = concentration of NH4Br
= 0.000604 mol / 0.5 L
= 0.001208 mol/L or 1.208 mmol/L or 1.20 M (rounded to two decimal places)

Therefore, the concentration of all ions present in a 58.7 mg NH4Br sample dissolved in 500 mL of solution is 1.20 M.

mols NH4Br = grams/molar mass

Then M NH4Br = mols/0.500L solution.
M = x
(NH4^+) = x
(Br^-) = x