Posted by **Natalie** on Thursday, April 11, 2013 at 2:04pm.

What value(s) of x from 0 to 2pi solve the following equation: cos squared x - cos x - 6 = 0

- Precalc with Trig -
**Steve**, Thursday, April 11, 2013 at 2:52pm
cos^2 - cos - 6 = 0

(cos-3)(cos+2) = 0

cos = 3 or -2

Bzzzt. |cos| <= 1, so not possible.

If there's a typo, fix it and apply the same steps.

- Precalc with Trig -
**Natalie**, Thursday, April 11, 2013 at 2:57pm
There isn't a typo this is the equation my professor gave us, thanks for the help!

## Answer This Question

## Related Questions

- Precalc with Trig - What value(s) of theta (0 less than or equal to theta less ...
- precalc/trig - olve for the interval [0, 2pi]. cos(x+ pi/4)+cos(x- pi/4)=1
- Trig - If cosx = 10/19 an pi < x < 2pi, find the exact value of cos x/2 ...
- Math - Solving for Trig Equations - Solve the following equation for 0 less than...
- trig - 2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3&#...
- Trig - How would I do this problem? Verify that each equation is an identity. ...
- Trig - Solve for 0<x<2pi ---> (2radical2)cos^2(x)-(radical2-2)cos(x)-1=...
- trig - Find all real numbers in the interval [0,2pi) that satisfy the equation. ...
- Precalc+trig - Solve tan(40/90) for the double angle cos(2theta). I know I use ...
- Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...

More Related Questions