Rents a van at daily rate of $19.95 plus .39/mile, another company will rent same van for $39.95 plus .29/mile. for what mileage are the costs the same?
39.95-19.95=20
.39-.29=.10
20/.10=200m
cost1 = .39x +19.95 , where x is the number of mile
cost2 = .29x + 39.95
when is cost1 = cost2 ?
.39x + 19.95 = .29x + 39.95
.1x = 20
x= 20/.1 = 200
the cost is the same at 200 miles
To find the mileage at which the costs are the same, we need to set up an equation. Let's denote the mileage as 'x' miles.
For the first company:
Cost = Daily rate + (per-mile rate * mileage) = $19.95 + (0.39 * x)
For the second company:
Cost = Daily rate + (per-mile rate * mileage) = $39.95 + (0.29 * x)
To find the mileage where the costs are the same, we can set these equations equal to each other:
$19.95 + (0.39 * x) = $39.95 + (0.29 * x)
To solve for x, we need to isolate the x term on one side of the equation:
0.39 * x - 0.29 * x = $39.95 - $19.95
Simplifying the equation gives:
0.1 * x = $20.00
Now divide both sides by 0.1 to solve for x:
x = $20.00 / 0.1
Therefore, the costs will be the same at 200 miles.