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March 1, 2015

March 1, 2015

Posted by **Rebekah** on Wednesday, April 10, 2013 at 8:46pm.

f(x)= (2x-1)e^(-x) on [0, 00)

- Math -
**Reiny**, Wednesday, April 10, 2013 at 8:57pmf ' (x) = (2x-1) e^(-x) ( -1) + 2 e^(-x)

= 0 for a max/min

e^(-x) (2 - (2x-1)) = 0

e^(-x) ( 3 - 2x) = 0

e^(-x) = 0 ----> no solution

or

3 - 2x = 0

x = 3/2

then f(3/2) = 2e^(-3/2) = 2/e^(3/2)

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