A buret is partially filled with NaOH solution, to a volume of 1.14 mL. A 20-mL sample of 0.1011 M HCl is titrated to a faint pink phenolphthalein endpoint. The final buret reading is 22.37 mL. What is the molartiy of the NaOH solution?

To find the molarity of the NaOH solution, we can use the equation:

M1V1 = M2V2

Where:
M1 = Molarity of the HCl solution
V1 = Volume of the HCl solution
M2 = Molarity of the NaOH solution
V2 = Volume of the NaOH solution

Let's plug in the given values into the equation:

M1 = 0.1011 M
V1 = 20 mL = 0.020 L
V2 = 22.37 mL - 1.14 mL = 21.23 mL = 0.02123 L

Now we can rearrange the equation and solve for M2 (molarity of NaOH):

M2 = (M1 * V1) / V2

M2 = (0.1011 M * 0.020 L) / 0.02123 L

M2 ≈ 0.0954 M

The molarity of the NaOH solution is approximately 0.0954 M.