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January 30, 2015

January 30, 2015

Posted by **Fifi** on Wednesday, April 10, 2013 at 12:44pm.

- physics -
**Steve**, Wednesday, April 10, 2013 at 1:02pmAssuming the stone is to be hurled vertically with velocity v,

h(t) = vt - 4.9t^2

h will reach maximum height at t=v/9.8 seconds. So, the max height H is

H(v) = v(v/9.8) - 9.8/2 * (v/9.8)^2

= v^2/9.8 - (v^2/9.8)/2

= v^2/19.6

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