Posted by **Caroline** on Wednesday, April 10, 2013 at 12:19am.

I'm having trouble understanding how to do complex fractions.. My book doesn't explain it very well..

12.

(x+3/12)/(4x-5/15)

14.

(2/x^2 + 1/x)/(4/x^2 - 1/x)

16.

(1/y + 3/y^2)/(y + 27/y^2)

If you could please explain how to begin the process I would appreciate it.

- Pre-Calculus -
**Bosnian**, Wednesday, April 10, 2013 at 2:07am
12.

3 / 12 = 3 / ( 3 * 4 ) = 1 / 4

5 / 15 = 5 / ( 5 * 3 ) = 1 / 3

( x + 3 / 12 ) / ( 4 x - 5 / 15 ) =

( x + 1 / 4 ) / ( 4 x - 1 / 3 ) =

( 4 x / 4 + 1 / 4 ) / ( 4 x * 3 / 3 - 1 / 3 ) =

[ ( 4 x + 1 ) / 4 ] / [ ( 12 x - 1 ) / 3 ] =

( 4 x + 1 ) * 3 / [ 4 * ( 12 x - 1 ) ] =

( 3 / 4 ) ( 4 x + 1 ) / ( 12 x - 1 ) =

3 * ( 4 x + 1 ) / [ 4 * ( 12 x - 1 ) ] =

( 12 x + 3 ) / ( 48 x + 4 )

14.

( 2 / x ^ 2 + 1 / x ) / ( 4 / x ^ 2 - 1 / x ) =

[ 2 / x ^ 2 + 1 * x / ( x * x ) ] / [ 4 / x ^ 2 - 1 * x / ( x * x ) ] =

( 2 / x ^ 2 + x / x ^ 2 ) / ( 4 / x ^ 2 - x / x ^ 2 ) =

[ ( 2 + x ) / x ^ 2 ] / [ ( 4 - x ) / x ^ 2 ] =

[ x ^ 2 * ( 2 + x ) / x ^ 2 ] / [ x ^ 2 * ( 4 - x ) / x ^ 2 ] =

( 2 + x ) / ( 4 - x )

16.

( 1 / y + 3 / y ^ 2 ) / ( y + 27 / y ^ 2 ) =

[ 1 * y / ( y * y ) + 3 / y ^ 2 ) ] / [ y * y ^ 2 / y ^ 2 + 27 / y ^ 2 ) ] =

( y / y ^ 2 + 3 / y ^ 2 ) / ( y ^ 3 / y ^ 2 + 27 / y ^ 2 ) =

[ ( y + 3 ) / y ^ 2 ] / [ ( y ^ 3 + 27 ) / y ^ 2 ) =

[ y ^ 2 * ( y + 3 ) / y ^ 2 ] / [ y ^ 2 ( y ^ 3 + 27 ) / y ^ 2 ) =

( y + 3 ) / ( y ^ 3 + 27 ) =

( y + 3 ) / [ ( y + 3 ) * ( y ^ 2 - 3 y + 9 ) =

1 / ( y ^ 2 - 3 y + 9 )

- Pre-Calculus -
**Reiny**, Wednesday, April 10, 2013 at 10:14am
12.

(x+3/12)/(4x-5/15)

first reduce those fractions to lowest terms

= (x + 1/4) / (4x - 1/3)

multipy top and bottom by 12 , the LCD

= (12x + 3)/(48x+4) or 3(4x+1)/(4(12x+1) )

14.

(2/x^2 + 1/x)/(4/x^2 - 1/x)

do it the same way, multiply top and bottom by x^2 , the LCD

= (2 + x)/(4 - x)

all done!

try the last one using the same method

- Pre-Calculus -
**Caroline**, Thursday, April 11, 2013 at 12:01am
Thank you both!

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