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math algebra

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the perimeter of a basketball court is 268 feet. the area is 4200 ft2. find the dimensions. using quadratics

  • math algebra - ,

    let the width be x
    and the length y
    2(x+y) = 268
    x+y = 134
    y = 134-x

    xy = 4200
    x(134-x) = 4200
    134x - x^2 - 4200=0
    x^2 - 134x + 4200 = 0
    (x - 50)(x - 84) = 0
    x = 50 or x = 84

    if x = 50 , then y = 134-50 = 84
    if x = 84, y = 50

    the rectangle is 50 by 84

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