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Posted by on Tuesday, April 9, 2013 at 8:09pm.

the perimeter of a basketball court is 268 feet. the area is 4200 ft2. find the dimensions. using quadractics

  • algebra - , Wednesday, April 10, 2013 at 1:48pm

    2L + 2W = 268

    L * W = 4200

    W = 4200/L

    2L + 2(4200/L) = 268

    Solve for L, then W.

  • alegebra - , Tuesday, March 31, 2015 at 6:02pm

    27262

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