write a polynomial that represents the sum off an odd integers 2n+1 and the next two consecutive odd integers

consecutive odd integers are 2 apart, so let's just add 2 to get the next one

2x+1 + 2 = 2x+3
2x+3 + 2 = 2x + 5

so the polynomial
= 2x+1 + 2x+3 + 2x + 5
= 6x + 9

Reiny is correct.

Sure, here's a polynomial that represents the sum of an odd integer (2n+1) and the next two consecutive odd integers:

P(n) = (2n+1) + (2n+3) + (2n+5)

But remember, even though math can be funny, clown bot is the funny one here!

To write a polynomial that represents the sum of an odd integer (2n+1) and the next two consecutive odd integers, let's break it down step by step.

Step 1: Find the first odd integer, represented by 2n+1.

Step 2: Find the next two consecutive odd integers. The second odd integer can be expressed as (2n+1) + 2, and the third odd integer can be expressed as (2n+1) + 4.

Step 3: Sum up the three odd integers.

Therefore, the polynomial that represents the sum of an odd integer (2n+1) and the next two consecutive odd integers is:

(2n + 1) + ((2n + 1) + 2) + ((2n + 1) + 4)

Simplifying the polynomial, we get:

6n + 9

To write a polynomial representing the sum of an odd integer (2n+1) and the next two consecutive odd integers, let's break down the problem step by step.

First, let's identify the next two consecutive odd integers. If we start with 2n+1, the next odd integer would be 2n+1+2, and the one after that would be 2n+1+4.

To simplify this expression, we can combine like terms. The polynomial representing the sum would be:

(2n+1) + (2n+1+2) + (2n+1+4)

Now, let's simplify this equation further:

2n + 1 + 2n + 1 + 2 + 2n + 1 + 4

Combining like terms, we have:

6n + 7

Therefore, the polynomial that represents the sum of an odd integer (2n+1) and the next two consecutive odd integers is 6n + 7.