Posted by **Tima** on Tuesday, April 9, 2013 at 5:12pm.

Find the equation of the line tangent to

f(x) = xe^-x

at the point where x = 0. What does this tell you about the behavior of the graph when x = 0?

- Calculus -
**Reiny**, Tuesday, April 9, 2013 at 6:47pm
first of all , when x = 0 , f(0) = 0

so the point is (0,0)

f'(x) = x(-e^-x) + e^-x

when x = 0

f'(0) = 0 + 1 = 1

equation of tangent : y = x

at (0,0) the function is increasing

## Answer This Question

## Related Questions

- Calculus - Find the equation of the line tangent to F(x) = xe^-x at the point ...
- Calculus - 1. Given the function f defined by f(x) = x^3-x^2-4X+4 a. Find the ...
- Math- calculus - Given f(x) = x ^ 3 - x ^ 2 -4x +4 Find the zeros of f. Write an...
- calculus - 1. Which of the following expressions is the definition of the ...
- Math--Calculus - Let y = f(x) be the continuous function that satisfies the ...
- Calculus - The function g is defined for x>0 with g(1)=2, g'(x)=sin(x+1/x), ...
- College Calculus - Let f(x) = 3x^2 - 2x + 1 a) write an equation of the line ...
- calculus - 5. Let f be the function given by f(x) = x3- 7x + 6. a. Find the ...
- Calculus - Find the slope m of the tangent line to the graph of the function at ...
- Calculus - Find the slope m of the tangent line to the graph of the function at ...

More Related Questions