Posted by **Jill** on Tuesday, April 9, 2013 at 2:18pm.

Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.

x^3+x^2+4x+4<0

The solution set is=

- Solve the polynomial inequality -
**Reiny**, Tuesday, April 9, 2013 at 2:28pm
x^3+x^2+4x+4<0

(x^2(x+1) + 4(x+1) < 0

(x+1)(x^2+4) < 0

well, x^2 + 4 is always positive, so the only way the whole thing < 0 if

x+1 < 0

x < -1

check:

good ol' Wolfram webpage

http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E3%2Bx%5E2%2B4x%2B4

notice where the curve is below the x-axis ?

- Solve the polynomial inequality -
**Jill**, Tuesday, April 9, 2013 at 2:38pm
Thank you!!!

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