Tuesday

July 29, 2014

July 29, 2014

Posted by **rinku** on Tuesday, April 9, 2013 at 1:31pm.

- algebra -
**Reiny**, Tuesday, April 9, 2013 at 2:43pmsimplified to

x^3 + 7x^2 - 21x - 27 = 0

try: x = ±1, ±3, ±7

on the second try, I got x=-1 to work

so (x+1) is a factor

by synthetic division I found

x^3 + 7x^2 - 21x - 27 = (x+1)(x^2 + 6x - 27) = 0

(x+1)(x+9)(x-3) = 0

x = -1, -9, and 3

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