February 21, 2017

Homework Help: Physics-

Posted by blur oh no on Tuesday, April 9, 2013 at 7:28am.

-Steam at 100 ¡ãC is mixed with 166.4 g of ice at ¨C32.8 ¡ãC, in a thermally insulated container, to produce water at 44.6 ¡ãC. Ignore any heat absorption by the container.
-Cwater = 4186. J/(kg ¡ãC)
-Cice = 2090. J/(kg ¡ãC)
-Lf,water = 3.33 ¡Á 105 J/kg
-Lv,water = 2.26 ¡Á 106 J/kg
Also,energy is required to bring all the ice up to 0 ¡ãC=11400J; energy is required to melt the ice into water at 0 ¡ãC=55400J; energy required to raise the temperature of this melted water to 44.6 ¡ãC =31100J;

<1>How much energy must then be supplied by the steam to change the state of 166.4 g of ice at ¨C32.8 ¡ãC to water at 44.6 ¡ãC?

<2>hat is the final mass of water in the cup at 44.6 ¡ãC?

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