Posted by **anonymous** on Tuesday, April 9, 2013 at 12:41am.

Solve -2(3x+2y-3)>12

- Algebra 2 -
**Bosnian**, Tuesday, April 9, 2013 at 1:45am
- 2 ( 3 x + 2 y - 3 ) > 12

- 2 * 3 x - 2 * 2 y - 2 * ( - 3 ) > 12

- 6 x - 4 y + 6 > 12

- 4 y > 12 + 6 x - 6

- 4 y > 6 x + 6

- 4 y > 6 ( x + 1 ) Divide both sides by - 4

If you multiply or divide both sides of an inequality by a negative number, you must reverse the direction of the inequality sign!

y < - 6 ( x + 1 ) / 4

y < -3 ( x + 1 ) / 2

y < 3 x / 2 - 3 / 2

- Algebra 2 -
**Bosnian**, Tuesday, April 9, 2013 at 1:48am
remark:

y < - 6 ( x + 1 ) / 4

are same as

y < 6 ( x + 1 ) / - 4

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