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July 31, 2014

July 31, 2014

Posted by **Agu** on Monday, April 8, 2013 at 11:55pm.

- physics -
**drwls**, Tuesday, April 9, 2013 at 2:21am(a) and (b) are separate problems, not multiple choices.

For the first case, letting di be the image distance from the lens, use the standard lens equation

1/6 + 1/di = 1/f = 1/10

1/di = 6/60 - 10/60 = -4/60 = -1/15

di = -15 cm

The image is "virtual" upright and magnified by a ratio |15/6| = 2.5

Now you do case b

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