Monday

December 22, 2014

December 22, 2014

Posted by **Agu** on Monday, April 8, 2013 at 11:55pm.

- physics -
**drwls**, Tuesday, April 9, 2013 at 2:21am(a) and (b) are separate problems, not multiple choices.

For the first case, letting di be the image distance from the lens, use the standard lens equation

1/6 + 1/di = 1/f = 1/10

1/di = 6/60 - 10/60 = -4/60 = -1/15

di = -15 cm

The image is "virtual" upright and magnified by a ratio |15/6| = 2.5

Now you do case b

**Answer this Question**

**Related Questions**

marymount academy - 1.An object 2.5cm high is placed 10cm from a converging lens...

calculus problem - the thin lens equation in physics is 1/s+1/S=1/f where s is ...

Physics: Lenses - 1) A convex lens with a focal lenght of 4.0cm is placed 20.0cm...

Physics - A convex lens of focal length 10 cm forms image of object placed 30 ...

Science Important - 1. A toy of height 18.4 cm is balanced in front of a ...

Physics - An object is placed 30mm in front of a lens. An image of the object is...

science - An object 3 cm is high is placed 24 cm away from a convex lens of ...

Geometric & Wave Optics - when an object is placed 10cm away from a lens; it is ...

Physics - A convex lens of focal length 2.5 cm is placed 4 cm from a small ...

CALCULUS - If you could give an explenation with the answers, that'd be ...