Posted by **Jeconiah ** on Monday, April 8, 2013 at 9:33pm.

solve for the value of x: 6log (x^2+1)-x=0. please help me because I do not have any idea in this topic.

- Please help me solve it. Math -
**Reiny**, Monday, April 8, 2013 at 10:18pm
6log(x^2+1)-x=0

6 log(x^2 + 1) = x

log(x^2 + 1) = x/6

x^2 + 1 = 10^(x/6)

wow ....

try Wolfram, since there is no "nice" way to solve this

http://www.wolframalpha.com/input/?i=x%5E2+%2B+1+%3D+10%5E%28x%2F6%29+

It says:** x = 0 or x = appr .416 or x = appr 13.63**

check:

x = 0

LS = 6log 1 - 0 = 0 = RS , OK

x = .416

LS = 6log(1.173056) - .416 = -.00008 , not bad

x = 13.63

LS = 6log(186.7769) - 13.63 = -.00206 , not bad

all three answers work

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