Posted by Jeconiah on Monday, April 8, 2013 at 9:33pm.
solve for the value of x: 6log (x^2+1)x=0. please help me because I do not have any idea in this topic.

Please help me solve it. Math  Reiny, Monday, April 8, 2013 at 10:18pm
6log(x^2+1)x=0
6 log(x^2 + 1) = x
log(x^2 + 1) = x/6
x^2 + 1 = 10^(x/6)
wow ....
try Wolfram, since there is no "nice" way to solve this
http://www.wolframalpha.com/input/?i=x%5E2+%2B+1+%3D+10%5E%28x%2F6%29+
It says: x = 0 or x = appr .416 or x = appr 13.63
check:
x = 0
LS = 6log 1  0 = 0 = RS , OK
x = .416
LS = 6log(1.173056)  .416 = .00008 , not bad
x = 13.63
LS = 6log(186.7769)  13.63 = .00206 , not bad
all three answers work