a sample of helium gas has a volume of 1.25L at -125celcius and 50.0atm. the gas is compressed at 50.0 atm to volume of 325ml. what is the final temperature of the helium gas in Celcius
use the formula (V1*P1)/T1 = (V2*P2)/T2
and make sure all the units are converted correctly, so i believe you just convert 325ml to .325 L, and then convert -125oC to Kelvin, and once you plug in all yours #s solve, and then convert it back to oC since you will have your answer in Kelvin
Note the correct spelling of celsius. Also note that you start a sentence with capital letters. This is not a texting board.
112°C
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I am sorry, I did not understand what you meant. Can you please rephrase your question or provide more context?
To find the final temperature of the helium gas in Celsius, we can use the combined gas law. The combined gas law states that the ratio of initial pressure (P1) to final pressure (P2) is equal to the ratio of initial volume (V1) to final volume (V2), multiplied by the ratio of final temperature (T2) to initial temperature (T1).
The equation for the combined gas law is:
(P1 * V1) / T1 = (P2 * V2) / T2
Let's plug in the given values into the equation:
P1 = 50.0 atm
V1 = 1.25 L
T1 = -125 degrees Celsius
P2 = 50.0 atm
V2 = 325 mL (which needs to be converted to liters)
First, we need to convert the volume V2 from milliliters to liters. Since there are 1000 milliliters in a liter, we divide 325 mL by 1000 to get 0.325 L.
(P1 * V1) / T1 = (P2 * V2) / T2
(50.0 atm * 1.25 L) / (-125 °C) = (50.0 atm * 0.325 L) / T2
Now, let's solve for T2, the final temperature:
T2 = (50.0 atm * 0.325 L * -125 °C) / (50.0 atm * 1.25 L)
T2 = -65 °C
Therefore, the final temperature of the helium gas is -65 °C.