What volume(ml) of 8.0 M solution is required to make 134.3 ml of 1.2 M solution
To find the volume of a higher concentration solution needed to make a lower concentration solution, we can use the equation:
\(C_1V_1 = C_2V_2\)
Where:
- \(C_1\) is the concentration of the higher concentration solution
- \(V_1\) is the volume of the higher concentration solution needed
- \(C_2\) is the concentration of the lower concentration solution
- \(V_2\) is the desired volume of the lower concentration solution
In this case, let's substitute the given values:
\(8.0M \times V_1 = 1.2M \times 134.3ml\)
Now, solve for \(V_1\):
\(\frac{{1.2M \times 134.3ml}}{{8.0M}} = V_1\)
\(\approx 20.05ml = V_1\)
So, approximately 20.05 ml of the 8.0 M solution is required to make 134.3 ml of the 1.2 M solution.