A hospital glucose solution is analyzed to verify its concentration. A 10.0 mL sample with a mass of 10.886 is evaporated to dryness. If the solid glucose residue has a mass of 0.648, what is the m/m% concentration?

To find the mass/mass (m/m%) concentration, you need to calculate the ratio of the mass of glucose residue to the mass of the original sample, then multiply by 100.

Step 1: Calculate the mass of glucose in the original sample.
Mass of glucose in the original sample = mass of the original sample - mass of the glucose residue
Mass of glucose = 10.886 g - 0.648 g
Mass of glucose = 10.238 g

Step 2: Calculate the m/m% concentration.
(m/m%) concentration = (mass of glucose / mass of the original sample) x 100
(m/m%) concentration = (10.238 g / 10.886 g) x 100
(m/m%) concentration = 93.97%

Therefore, the m/m% concentration of the hospital glucose solution is 93.97%.

To find the mass/mass percent concentration of a glucose solution, we need to calculate the ratio of the mass of the glucose residue to the mass of the original sample, and then convert it to a percentage.

First, we need to find the mass of the original sample by subtracting the mass of the glucose residue from the mass of the evaporated sample:

Mass of original sample = Mass of evaporated sample - Mass of glucose residue
= 10.886 g - 0.648 g
= 10.238 g

Next, we calculate the mass/mass percent concentration by dividing the mass of the glucose residue by the mass of the original sample and multiplying by 100:

Mass/mass percent concentration = (Mass of glucose residue / Mass of original sample) x 100
= (0.648 g / 10.238 g) x 100
≈ 6.33%

Therefore, the m/m% concentration of the hospital glucose solution is approximately 6.33%.