1L of a .2M solution of Ethanoic acid is altered by adding 5.00g of sodium butanoate. what is the pH of the new solution
To determine the pH of the new solution, we need to understand the reaction that occurs when ethanoic acid (CH3COOH) reacts with sodium butanoate (CH3CH2CH2COONa). This reaction is an acid-base reaction, resulting in the formation of sodium ethanoate (CH3COONa) and butanoic acid (CH3CH2CH2COOH).
First, let's calculate the number of moles of sodium butanoate added to the solution:
Mass of sodium butanoate = 5.00g
Molar mass of sodium butanoate = molar mass of Na + molar mass of butanoate = 23.0g/mol + 96.1g/mol = 119.1g/mol
Number of moles of sodium butanoate = Mass / Molar mass
= 5.00g / 119.1g/mol
≈ 0.042 moles
Now, we need to determine the reaction between the ethanoic acid and sodium butanoate. The sodium butanoate will react with the ethanoic acid to form sodium ethanoate and butanoic acid in a one-to-one ratio.
Since ethanoic acid is a weak acid, it will partially ionize in the solution. The reaction can be represented as:
CH3COOH + CH3CH2CH2COONa ⇌ CH3COONa + CH3CH2CH2COOH
In this reaction, ethanoic acid (CH3COOH) donates a proton (H+) to sodium butanoate (CH3CH2CH2COONa) to form sodium ethanoate (CH3COONa) and butanoic acid (CH3CH2CH2COOH).
The sodium ethanoate formed in the reaction will hydrolyze in water to produce hydroxide ions (OH-), causing an increase in the pH of the solution.
To calculate the pH of the new solution, we need to know the concentration of the sodium ethanoate (CH3COONa) formed, as well as the dissociation constant (Ka) of ethanoic acid.
However, the given information does not provide the concentration of ethanoic acid or sodium butanoate. Without this information, it is not possible to accurately calculate the pH of the new solution.
If you have the concentration of ethanoic acid and sodium butanoate, please provide it so that we can proceed with the pH calculation.