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November 26, 2014

November 26, 2014

Posted by **Liz** on Monday, April 8, 2013 at 2:34pm.

b) assume that half of the 200 passengers are men, what doorway height satisfies the condition that there is a .95 probability that this height is greater than the mean height of 100 men?

- Statistics -
**anoynomous**, Monday, April 8, 2013 at 2:49pma)

The value of z such that P(Z<z)= 0.95 is z = 1.6449

Solving for x:

z =1.6449=(x-69.0)/2.8

x = 1.6449*2.8+69 = 73.6

b)

Solving for xbar:

z =1.6449=(xbar-69.0)/(2.8/sqrt(100))

xbar = 1.6449*0.28+69 = 69.5

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