dr. halite combined sodium metal with chlorine gas to make sodium chlorine (table salt). The chemical reaction used up all of the metal and sll of the gas. If dr halite made 116 g of table salt and started with 68 g of chlorine gas, then how many grams of sodium metal did he start with?

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To find the number of grams of sodium metal that Dr. Halite started with, we need to use stoichiometry, which relates the amounts of substances in a chemical reaction.

First, let's write out the balanced chemical equation for the reaction between sodium and chlorine:

2 Na + Cl2 → 2 NaCl

From the balanced equation, we can see that 2 moles of sodium react with 1 mole of chlorine to produce 2 moles of sodium chloride.

To find the number of moles of chlorine gas that reacted, we can use its molar mass. The molar mass of chlorine (Cl2) is approximately 70.9 g/mol.

Number of moles of chlorine gas used = mass of chlorine gas / molar mass of chlorine gas
= 68 g / 70.9 g/mol

Now, we can apply the stoichiometric ratio from the balanced equation to determine the number of moles of sodium metal used. Since the ratio is 2 moles of sodium to 1 mole of chlorine gas:

Number of moles of sodium used = (2 moles of sodium / 1 mole of chlorine gas) * (moles of chlorine gas used)

Finally, we can calculate the mass of sodium metal used:

Mass of sodium used = Number of moles of sodium used * molar mass of sodium
= (moles of sodium used) * (22.99 g/mol)

By substituting the values into the equations, we can find the mass of sodium metal used by Dr. Halite.