Posted by thomas on .
Please help!!
*f(x)= x(x+6)^1/2 find two x intercepts.
Then show that f'(x)=0 at some point between the 2 x intercepts.
*Use mean value theorem for f(x)= x(x^23x+1) for interval [1,4]
I FOUND DERIAVITIVE WHICH IS 3X^26X+1.THEN?
*find all critical numbers find all intervals on which the function is increasing or decreasing. lable extrma.
I FOUND MY DERIVATIVE WHICH IS 32X/(X^216)^2
CRITICAL NUMBERS ARE 0,4 AND 4.
SO WHAT DO i DO NEXT

calculus 
bobpursley,
the two x intercepts are 0, and 6
set the derivative equal to zero, and find x
f'(x)=(x+6)^1/2 + x/2 *1/(x+6)^2=0
x+6 + x/2=0
3x=12
x=4
***
find f(1), and f(4)
f(1)=1
f(4)=20
this means there is a zero between x=1,4
*****
I wonder on this third question what is the function? Putting parts of several qustion on one question is very confusing. 
calculus 
thomas,
f(x)=x^2/x^216

calculus 
thomas,
i got this. thnks