Posted by **dingbat** on Sunday, April 7, 2013 at 4:15pm.

Q:The ratio of the perimeters of two square is 5 to 4. If the area of the smaller square is 36 units, what is the area of the larger square?

A: 56.25

My teacher told us the answer, 56.25, so that we could correct it. But I don't understand how she got the answer at all, so can someone please help me solve the question so that I could understand how to do it.

- 7th grade math -
**dingbat**, Sunday, April 7, 2013 at 4:27pm
can someone please help me :0

- 7th grade math -
**Bosnian**, Sunday, April 7, 2013 at 4:45pm
a1 = the side length side of the smaller square

a2 = the side length side of the larger square

The area of the smaller square is 36

A1 = a1 ^ 2 = 36

a1 ^ 2 = 36

a1 = sqrt ( 36 ) = 6

Perimeter of square = 4 side length

In this case :

4 a2 / 4 a1 = 5 / 4

a2 / a1 = 5 / 4

a2 / 6 = 5 / 4 Multiply both sideas by 6

a2 = 5 * 6 / 4 = 30 / 4 = 15 / 2 = 7.5

The area of the larger square :

A2 = a2 ^ 2 = 7.5 ^ 2 = 56.25

- 7th grade math -
**dingbat**, Sunday, April 7, 2013 at 4:46pm
thank you :D

- 7th grade math -
**Bosnian**, Sunday, April 7, 2013 at 4:47pm
a1 = the length side of the smaller square

a2 = the length side of the larger square

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