7th grade math
posted by dingbat .
Q:The ratio of the perimeters of two square is 5 to 4. If the area of the smaller square is 36 units, what is the area of the larger square?
My teacher told us the answer, 56.25, so that we could correct it. But I don't understand how she got the answer at all, so can someone please help me solve the question so that I could understand how to do it.
can someone please help me :0
a1 = the side length side of the smaller square
a2 = the side length side of the larger square
The area of the smaller square is 36
A1 = a1 ^ 2 = 36
a1 ^ 2 = 36
a1 = sqrt ( 36 ) = 6
Perimeter of square = 4 side length
In this case :
4 a2 / 4 a1 = 5 / 4
a2 / a1 = 5 / 4
a2 / 6 = 5 / 4 Multiply both sideas by 6
a2 = 5 * 6 / 4 = 30 / 4 = 15 / 2 = 7.5
The area of the larger square :
A2 = a2 ^ 2 = 7.5 ^ 2 = 56.25
thank you :D
a1 = the length side of the smaller square
a2 = the length side of the larger square