PreAlgebra
posted by Nancy on .
Find 3 consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 5 times the third.

6,7,8

let the first be x1
let the second be x
let the third be x+1
direct translation from English to Math
(math is a language)
(x1)(x+2  x = 5(x+1) + 1
x^2  1 x = 5x + 5 + 1
x^2  6x 7 = 0
(x7)(x+1)
x = 7 or x = 1, but x is to be positive
so the first is 6
the second is 7
the third is 8