Posted by Daniel on Sunday, April 7, 2013 at 2:14pm.
The Question is:
The value of a new car depreciates at a rate of 12% per year.
1)Write an equation to represent the approximate value of a car purchased for $23 000.
2)Determine the value of the car two years after it is purchased.
3)Approximately how many years will it take until the car is worth $2300?
I have received answers that differ for this question. I request feedback for further understanding what must be done.
The following is an example of how the answers I've received are different:
ex.1
a) V= C  rtC,
Eq: V = C(1  rt).
V = value.
C = cost.
r = rate expresed as a decimal.
t = time in years.
b) V = 23000(1  0.12*2),
V = 23000 * 0.76 = 17480.
c) V = 23000(1  0.12t) = 2300,
23000(1  0.12t) = 2300,
Divide both sides by 23000:
1  0.12t = 0.1,
0.12t = 0.1  1 = 0.90,
t = 0.90 / 0.12 = 7.5 yrs.
OR
a) A=23000(10.12)^1
A= 20240
b) A=23000(10.12)^2
A=17 811.20
c) 2300 = 23000(.88)^n
0.1 = (.88)^n
n = (log 0.1) / (log 0.88)
=18.01 years

math  Reiny, Sunday, April 7, 2013 at 4:02pm
No need for confusion:
This is an exponential function
value= 23000(.88)^t , where t is the number of years
2. when t=2
value = 23000(.88)^2 = $17811.20
3.
2300 = 23000(.88)^t
.1 = .88^t
take log of both sides
log .1 = log .88^t
log .1 = t log .88
t = log .1/log .88 = 18.01 or appr 18 years

math  Daniel, Sunday, April 7, 2013 at 6:27pm
Great this helps alot, was worried I screwed up something
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