Friday

August 29, 2014

August 29, 2014

Posted by **Anne** on Sunday, April 7, 2013 at 1:48pm.

tanθ = 0, all real numbers

I know the answer is πn, but I don't understand how they got this. I get that tanθ = 0 on π and 2π on the unit circle, so did they just put n on the end of π because of this?

- Trig -
**Reiny**, Sunday, April 7, 2013 at 3:53pmtanŲ = sinŲ/cosŲ = 0

in sinŲ/cosŲ = 0 , that is only possible if sinŲ = 0

and you should know that the basic sine curve has zeros at 0 , π and 2π

since the period of sinŲ = π,

a new answer can be obtained by simply adding/subtracting multiples of π (or nπ) to any anwer

So why not start with 0 + nπ = nπ

**Related Questions**

trig - solve exactly over the indicated interval: cot(theta)=0, all real numbers

Solving Trig equation - Solve the trig equation exactly in the interval 0≤...

trig - cosθ =5/13 with -π/2 < θ <0 find each of the ...

TRIG - Solve this equation on the interval 0 θ < 2π. Round your ...

college Trig - Solve this equation on the interval 0 θ < 2π. Round ...

Trig - Solve exactly over 0 ≤ θ < 2π secx + tanx = 1

math (final trig problem) - Solve for x on the interval [0,π/2): cos^3(2x...

Trig - The set of solution(s) of 2 cos^2 (θ) - 13 cos(θ) + 6 = 0 that ...

trig - Solve exactly over the indicated interval: 2sinx+cscx=3, 0<theta<...

trig - find cos(θ)ˏsin(θ)ˏtan(θ), if cot (2θ)=5/12...