Posted by **Anne** on Sunday, April 7, 2013 at 1:48pm.

Solve the trig equation exactly over the indicated interval.

tanθ = 0, all real numbers

I know the answer is πn, but I don't understand how they got this. I get that tanθ = 0 on π and 2π on the unit circle, so did they just put n on the end of π because of this?

- Trig -
**Reiny**, Sunday, April 7, 2013 at 3:53pm
tanŲ = sinŲ/cosŲ = 0

in sinŲ/cosŲ = 0 , that is only possible if sinŲ = 0

and you should know that the basic sine curve has zeros at 0 , π and 2π

since the period of sinŲ = π,

a new answer can be obtained by simply adding/subtracting multiples of π (or nπ) to any anwer

So why not start with 0 + nπ = nπ

- Trig -
**Jacob**, Thursday, November 12, 2015 at 6:46pm
Use trigonometric identities to solve tan(2θ)+tan(θ)=0 exactly for 0≤θ≤π. If there is more than one answer, enter your answers as a comma separated list

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