Posted by abdul rahman on .
A current I=2 Amperes flows in a circular single loop coil of radius R=10 cm.
(a) Evaluate the magnitude of the magnetic field (in Tesla) at a point P on the axis of the coil, and a distance z =5 cm away from the plane of the coil itself.
Now consider two Nturn circular coils of radius R, each perpendicular to the axis of symmetry, with their centers located at z=±l/2 . There is a steady current I flowing in the same direction around each coil, as shown in the figure below.
(b) Assuming the N=100, I=2 Amperes, R=10 cm, l=2 cm calculate the magnitude of the magnetic fied (in Tesla) at a distance z=0.5 cm from the midpoint between the centers of the two coil.
(c) Evaluate the first derivative with respect to z of the magnetic field calculated in part (b) using the same values for the parameters. Express your answer in Tesla per meter.
C) Calculate the second derivative with respect to z of the magnetic field calculated in part (b) using the same values for the parameters. Express your answer in Tesla per meter^2

physics 
FLu,
a)0.0000090020201102748
b)0.0025
c) First part 0.00358179
Anyone for second part of part c) Tesla per metre square? 
physics 
FLu,
Third and Last part of c) is 0 by the way.
second part for c) Tesla per square meter please? 
physics 
Mirt,
Anyone for second part for c) Tesla per square meter please?

physics 
Trek,
Anyone for C) Tesla per square meter please?

physics 
FLu,
Abdul Rahman do you have Problem 2 please?

physics 
P,
Yes please Problem 2!

physics 
Ruben,
URGENT !! PROBLEM 2 !! D:

physics 
FLu,
Problem 2 is answered now Ruben, look at my profile. Do you have by any chance Problem 3 c) second part?
tesla in square meter 
physics 
Luiis,
The second part in c) problem 3 it's tricky ... i didn't got yet. ):
Please angle in the Aurora Zone ?? 
physics 
FLu,
That is easy Luis it is 18.
Please let me know anyone who cracks second answer part c)?
thanks 
physics 
Mag,
Please answer second part tesla in meters problem 3) c) !

physics 
Luiis,
YEAH I GOT IT PROBLEM 3 c) secnd part 0.687332867 !!!
SO PLEASE PROBLEM 4 (b) ??!!!
Hurry up i got 10 minutes to check !!!!! 
physics 
FLu,
Thanks Luis, it is below!
4)b)
(pi*B^2*L^4*omega)/R 
physics 
Luiis,
:)Thank youu

physics 
stEvE,
what is the answer for 2) a) n 2)b)

physics 
stEvE,
answer for that intuition problem???