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August 1, 2014

August 1, 2014

Posted by **DW** on Sunday, April 7, 2013 at 11:25am.

and if it forms two possible triangles solve all unknown angles and sides

Angle A=116 degrees

a=10

b=11

- Pre-Calculus -
**Reiny**, Sunday, April 7, 2013 at 11:35amOne.

Assuming you are using the standard notoation that

b is the side opposite angle B etc.

sinB/11 = sin116°/10

sin B = .9886

angle B = appr 81.4° or appr 98.6°

but the latter is not possible since a triangle cannot have 2 obtuse angles

so B = 81.4° is the only angle possible,

thus only one triangle.

I will leave it up to you to find the other angle and side.

- Pre-Calculus -
**DW**, Sunday, April 7, 2013 at 11:39ambut if you add 81.4 (measure of angle B) plus 116 (measure of angle A) you get 197.368 which is over 180 degrees....

so that would make measure of angle C negative which is why I'm confused

- Pre-Calculus -
**DW**, Sunday, April 7, 2013 at 11:39ambut if you add 81.4 (measure of angle B) plus 116 (measure of angle A) you get 197.368 which is over 180 degrees....

so that would make measure of angle C negative which is why I'm confused

- Pre-Calculus -
**DW**, Sunday, April 7, 2013 at 11:39ambut if you add 81.4 (measure of angle B) plus 116 (measure of angle A) you get 197.368 which is over 180 degrees....

so that would make measure of angle C negative which is why I'm confused

- Pre-Calculus -
**Reiny**, Sunday, April 7, 2013 at 12:05pmOf course you are right, silly of me not to even check for the obvious.

I was too concerned about the two obtuse angles.

c

so....

No such triangle is possible.

- Pre-Calculus -
**DW**, Sunday, April 7, 2013 at 12:09pmthank you so much!!!

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