Posted by **MadiB PLEASE HELP :(** on Sunday, April 7, 2013 at 9:20am.

1. Calculate the energy change (q) of the surroundings (water) using the enthalpy equation

qwater = m × c × ΔT.

We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. Show ALL your work.

The water has absorbed the heat of the metal. So, qwater = qunknown metal

## Answer This Question

## Related Questions

- chemistry - Insert a complete data table, including appropriate significant ...
- Chemistry - the specific heat capacity of gold is .13 J/g°C. Calculate the ...
- Chemistry Help! - the specific heat capacity of gold is .13 J/g°C. Calculate the...
- chemistry - 1. a) 50ml of water at 46.9°C were mixed with 50ml of water at 25.1°...
- chemistry - If someone could see if I have the right answers, and if I don't ...
- Chemistry (check) - Not sure if these are right 1) What is the Molar Enthalpy ...
- chemistry - 1. Given that 50 grams of ice is heated at -20.0 °C to steam at 135....
- Chemistry - Two 20.0-g ice cubes at –20.0 °C are placed into 295 g of water at ...
- intro chem HELp please - 1. Zinc is often used to calibrate calorimeters because...
- ap chemistry - A calorimeter contains 20.0 of water at 12.5 . When 2.20 of (a ...

More Related Questions