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December 21, 2014

December 21, 2014

Posted by **marie darling** on Sunday, April 7, 2013 at 12:08am.

There are two solutions, A and B, with A < B and A and B in radians to 4 decimal places.

- Precalculus -
**marie darling**, Sunday, April 7, 2013 at 12:09amle= (less than or equal to)

lt= (less than)

- Precalculus -
**Reiny**, Sunday, April 7, 2013 at 12:45amHere is how I do these.

First I decide in which quadrant the angles are.

Since sinx is negative, x must be in quads III or IV.

I then find the angle in standard position by finding sin^-1 (+.36) which is

.36826.. (in radians) or 21.1 degrees

so x = pi + .36826 or x = 2pi - .36826

in degrees x = 201.1 or 338.9

- Precalculus -
**marie darling**, Sunday, April 7, 2013 at 10:50amThank you for your help!

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