Posted by Becky on Saturday, April 6, 2013 at 9:42pm.
PE → KE1
KE1 → Work(fr) +KE2 =>
PE → Work(fr) +KE2
If the initial height is ‘h₁’,
the height of the horizontal section is ‘h₂’,
the length of the rough section is ‘s’, then
mg (h₁-h₂)=μmgs +mv²/2,
v=sqrt{ 2g[(h₁-h₂)-μs]}.
---
h₂=gt²/2,
t=sqrt(2h₂/g).
x=vt,
v(y)=gt.
V(near the ground)=sqrt{v²+v(y)²}
Thank you!
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