2.)If f(x)=3x,g(x)=x-3,and h(x)= the square root of x, find (fogox)(X). I really didn't get this will someone please show me how to do it?
This I what I did to solve for it:
3(x-3)
3(he square root of 25-3
3(5-3)
15-9=6
Ok here is another way I solved for it but I am still not sure if I am doing any of the work right.
f(g(h))(25)
f(g(square root of f(x)))(25)
f(g(1.7))(25)
f(1.7-3)
F(-1.3)
f(25)=3(25)
f(25)=75
Which one is correct and if they are both wrong will you help me get the right answer and understand how to do it?
The correct answer was 6.
To find (fogox)(X), we need to follow the composition of functions.
First, let's find g(h(x)):
h(x) is the square root of x, so we have h(x) = √x.
Now, substitute g(x) = x - 3 into h(x):
g(h(x)) = h(x) - 3
g(h(x)) = √x - 3
Next, let's find f(g(h(x))):
f(x) = 3x, so we have f(g(h(x))) = 3(g(h(x))).
Substitute g(h(x)) = √x - 3 into f(x):
f(g(h(x))) = 3(√x - 3)
So, (fogox)(X) is 3(√x - 3).
Now, let's evaluate it for x = 25:
(fogox)(25) = 3(√25 - 3)
(fogox)(25) = 3(5 - 3)
(fogox)(25) = 3(2)
(fogox)(25) = 6