Posted by **Chad** on Saturday, April 6, 2013 at 2:33pm.

A boat is traveling on a bearing of 25 degrees East of North at a speed of 4 knots (a knot is 1.852 km/h). After traveling for 3 hours, the boats heading is changed to due South and it travels for an additional 2 hours at 5 knots. Using a Vector diagram, what is the resultant?

- physics -
**Henry**, Monday, April 8, 2013 at 9:01pm
V1 = 4 * 1.852km/h = 7.408 km/h.[65o].

d1 = 3h * 7.408km/h = 22.224 km/h[65o].

V2 = 5 * 1.852km/h = 9.26 km/h.[270o].

d2 = 9.26km/h * 2h = 18.52 km[270o].

R = d1 + d2.

R = 22.224km[65o] + 18.52 km[270o]

X = 22.224*cos65 = 9.39 km.

Y = 22,224*sin65 + 18.52*sin270=1.62 km

tanA = Y/X = 1.62/9.39 = 0.17271

A = 9.8o

R = X/cosA = 9.39/cos9.8=9.53 km[9.8o].

= Resultant.

## Answer this Question

## Related Questions

- physics - A boat is traveling on a bearing of 25 degrees East of North at a ...
- physics - A boat is traveling on a bearing of 25 degrees East of North at a ...
- physics - A boat is traveling on a bearing of 25 degrees East of North at a ...
- physics - A boat is traveling on a bearing of 25 degrees East of North at a ...
- math - . A boat is travelling on a bearing of 25° east of north at a speed of 5 ...
- physics - A boat is traveling on a bearing of 25 degrees East of North at a ...
- physics - Two vehicles with the same mass collide and lock together traveling 28...
- physics - Two vehicles with the same mass collide and lock together traveling 28...
- math - Two fishing boats depart a harbor at the same time, one traveling east, ...
- Calculus - Suppose that two boats leave a dock at different times. One heads due...