Friday

March 6, 2015

March 6, 2015

Posted by **Gummy** on Saturday, April 6, 2013 at 1:09pm.

Outcome 1-spot 2-spot 3-spot 4-spot 5-spot 6-spot

Frequency 7 12 8 15 11 7

Using the “Goodness of Fit” test at the 5% level of significance, test whether the null hypothesis that the given die is fair is true. (Hint: If the die is fair, each “spot” has the same chance of appearing). Use the back of the page for work if needed.

- Statistics -
**PsyDAG**, Saturday, April 6, 2013 at 2:57pmUse the Chi-square (X^2) method.

X^2 = ∑ (O-E)^2/E, where O = observed frequency and E = expected frequency.

∑ = sum of all the cells.

E = (column total * row total)/grand total

df = n - 1, where n = number of cells

Look up value in X^2 table in the back of your textbook.

**Answer this Question**

**Related Questions**

physics - Two charges, -17 and +3.6 µC, are fixed in place and separated by 3.2...

physics 2 - Two charges, -17 and +3.6 µC, are fixed in place and separated by 3....

physics - Jack, jill and spot go out for a picnic at the side of the river. ...

physics 20 - Jack, jill and spot go out for a picnic at the side of the river. ...

math - A specially made pair of dice has only one- and two-spots on the faces. ...

physics - help! Two charges A and B are fixed in place, at different distances ...

physics - Two charges A and B are fixed in place, at different distances from a ...

Physics - Two charges A and B are fixed in place, at different distances from a ...

Physics - Two charges A and B are fixed in place, at different distances from a ...

Geological Events - Hot spot volcanoes appear as volcanic chains in the middle ...