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Posted by on Saturday, April 6, 2013 at 1:31am.

Light is shining perpendicularly on the surface of the earth with an intensity of 680 W/m2. Assuming that all the photons in the light have the same wavelength (in vacuum) of 478 nm, determine the number of photons per second per square meter that reach the earth.

  • physics - , Saturday, April 6, 2013 at 5:53am

    Energy =Power x time =680 W/m2 x 1 second =680 Joule/m2
    Energy of 1 photone = hf =hc/λ
    Number of photones =Energy/energy of 1 photon =
    N=680• λ/hc=680•478•10⁻⁹/6.63•10⁻³⁴•3•10⁸=…

  • physics - , Sunday, April 7, 2013 at 1:12am

    Thank You So much

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