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Physics

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A simple motor has N=250 turns of wire on a coil measuring 12 cm \times \, 4 cm. It's resistance is R=10 ohms. The magnetic field is B=1 T.

(a) How much current (in Ampere) in the coil is needed to produce a maximum torque of 40 Nm?

b) What maximum EMF (in Volts) is needed to drive the motor at 50 Hz if the current is constant?

  • Physics - ,

    (a)
    Torque is
    M=p⒨•B•sinα
    p⒨=NIA
    If M(max) =sin α=1
    M(max)=NIAB,
    I= M(max)/NAB =
    =40/250•0.12•0.04•1=33.3 A
    (b)
    ℰ=-dΦ=-d(NBAsinωt)/dt=
    =-NBAωcosωt
    ℰ(max)=NBAω=2πNBAf=
    =2π•250•1•0.12•0.04•50=377 V

  • Physics - ,

    Thanks

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