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March 30, 2015

March 30, 2015

Posted by **Lorie** on Friday, April 5, 2013 at 9:28pm.

Thanks in advance! I appreciate all the help! :)

- college math -
**Steve**, Saturday, April 6, 2013 at 5:23amif you know what direct and inverse variations are, then you know that

w = kxy^2/z^3

plug in w,x,y,z to get k:

3=k(4)(4)/64

3 = k/16

k=48 so,

w = 48xy^2/z^3

Now plug in the new x,y,z to get w, since we now know k.

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