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November 28, 2014

November 28, 2014

Posted by **Lorie** on Friday, April 5, 2013 at 3:04pm.

- college math -
**Reiny**, Friday, April 5, 2013 at 3:12pmW = k x√y/z^3

so W=3, x=4,y=2, z=4

3 = k(4√2/64

k = 192/(4√2) = 48/√2

so if x = 5,y=5,z=4

W = (48/√2)(5)(√5)/64

= 15√5/(3√2) or after rationalizing the denominator

= 15√10/8 = appr 5.929

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