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October 30, 2014

October 30, 2014

Posted by **Lorie** on Friday, April 5, 2013 at 2:34pm.

Thanks in advance!

- college math -
**Reiny**, Friday, April 5, 2013 at 2:45pmrate going to store --- x mph

rate coming back ----- x-1 mph

(8/60)x = (13/60)(x-1)

times 60

8x = 13(x-1)

8x - 13x = -13

-5x = -13

x = 2.6

So he walked to the store at 2.6 mph

check:

(8/60)(2.6) = .34666...

(13/60)(1.6) = .34666... , ---> same distance

- college math -
**Steve**, Friday, April 5, 2013 at 2:47pmdistance = speed*time, and the two distances are the same, so

8s = 13(s-1)

s = 13/5 = 2.6 mph

Note that we can mix minutes and mph, because the same factor would be applied to both sides if we converted everything to minutes or hours. As long as the units on both sides match, we are ok.

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