If your equation of the line for you SAM analysis is y=1x+0.3436, what is the concentration of MgO in W/w% in your unknown with a mass of 0.1018?
To calculate the concentration of MgO in weight percent (w/w%) in your unknown sample, we need to use the equation of the line provided: y = 1x + 0.3436.
The equation represents a linear relationship between the measured y-values (in this case, concentration) and the x-values (in this case, the mass of the unknown sample).
In this equation, the coefficient of x is 1, which implies that the concentration is directly proportional to the mass of the sample.
The constant term in the equation, 0.3436, represents the intercept of the line. In the context of this problem, it could represent the concentration at zero mass. However, since mass cannot be zero, it indicates a non-zero concentration at the assumed mass.
Given that the mass of the unknown sample is 0.1018, we can substitute this value into the equation:
y = 1(0.1018) + 0.3436
Simplifying the equation:
y = 0.1018 + 0.3436
y = 0.4454
Therefore, the concentration of MgO in weight percent (w/w%) in your unknown with a mass of 0.1018 is 0.4454%.