Posted by Piggy on Friday, April 5, 2013 at 12:23am.
write a fourth degree polynomial function a leading coefficient o 1 given three of its zeros are 1, 3 and 2i, then rewrite it in simplified form.

Algebra II  Reiny, Friday, April 5, 2013 at 1:30am
The key concept here is that imaginary numbers always appear as conjugates
so if 2i is a zero, so is 2a
so we would have x = ±2i
x^2 = 4i^2
x^2 = 4
so x^2 + 4 is a factor
the polynomial is
f(x) = (x+1)(x3)(x^2 + 4)
I will leave it up to you to expand it, but I would consider the factored form more simplified than the expanded form.
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