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Analytical chemistry

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A 25.0-mL solution of 0.0660 M EDTA was added to a 33.0-mL sample containing an unknown concentration of V3 . All V3 present formed a complex, leaving excess EDTA in solution. This solution was back-titrated with a 0.0450 M Ga3 solution until all the EDTA reacted, requiring 13.0 mL of the Ga3 solution. What was the original concentration of the V3 solution?

  • Analytical chemistry - ,

    EDTA reacts with both V3+ and Ga3+ in a 1:1 stoichiometric ratio.
    Therefore, the moles of EDTA added is equal to the sum of the moles of V3+ present and Ga3+ added.
    moles of EDTA= moles V3 + moles of Ga3
    (0.025 L)(0.0660 M EDTA)= (x moles of V3) + (0.013 L)(0.0450 M Ga3)
    moles of V3= 0.001065
    M of V3 = 0.001065 moles / 0.033 L
    M of V3 = 0.032 moles/L

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