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November 26, 2014

November 26, 2014

Posted by **sancho** on Thursday, April 4, 2013 at 1:47pm.

a) Approximate the percent error in computing the length of the hypotenuse.

b) Estimate the maximum allowable percent error in measuring the angle of the error in computing the length of the hypotenuse cannot exceed 1%

- Calculus -
**Steve**, Thursday, April 4, 2013 at 3:13pm27°45' = 27.75° = 0.484 radians

15' = .25° = 0.00436 radians

the hypotenuse h is

h = 9.5 cscθ

h(.484) = 20.416

dh = -9.5 cscθ cotθ dθ

for dh <= 1% at θ=.484

.00484 >= 9.5(2.149)(1.902) dθ

dθ <= 0.012%

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