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November 24, 2014

November 24, 2014

Posted by **Irma** on Thursday, April 4, 2013 at 10:14am.

- Math Technology -
**Reiny**, Thursday, April 4, 2013 at 10:53amI made a diagram of a parallogram, then drew in the diagonal to show the resultant, called it R

Looking at a triange, I have sides 20 and 500 with a contained angle of 105°

R^2 = 20^2 + 500^2 - 2(20)(500)cos105°

R = 505.546 mph

repeating for the side at 30

R2 = 508.59 mph

for first case: R = 505.546

sinØ/500 = sin105/505.546

Ø = 72.8°

so bearing = 72.8 - 30 = 42.8°

for 2nd case R2 = 508.59

sinØ/500 = sin105/508.59

Ø = 71.7

so bearing = 71.7 - 30

= 41.7

his bearing should be between 41.7° and 42.8°

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