Posted by **joe** on Thursday, April 4, 2013 at 1:30am.

In the diagram, circle A is tangent to circle C, and segment BE is tangent to circle A. The radius of circle A is 11 meters and the radius of circle C is 8 meters. Find the area of triangle ABE to the nearest square meter.

- geometry -
**Reiny**, Thursday, April 4, 2013 at 8:07am
I must assume that A and B are the centres of your two circles for this to make sense.

Join AE, and you will have a right angles triangle AEB

with AE=11, AB = 19 , and BE = x

x^2 + 11^2 = 19^2

x^2 = 240

x = √240

so the area = (1/2) base x height

= (1/2)(√240)(11)

= 22√15 or appr 85.2

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