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In the diagram, circle A is tangent to circle C, and segment BE is tangent to circle A. The radius of circle A is 11 meters and the radius of circle C is 8 meters. Find the area of triangle ABE to the nearest square meter.

  • geometry - ,

    I must assume that A and B are the centres of your two circles for this to make sense.
    Join AE, and you will have a right angles triangle AEB
    with AE=11, AB = 19 , and BE = x
    x^2 + 11^2 = 19^2
    x^2 = 240
    x = √240

    so the area = (1/2) base x height
    = (1/2)(√240)(11)
    = 22√15 or appr 85.2

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