Posted by Seth on Thursday, April 4, 2013 at 1:26am.
Solve for the value of x: 6log(x^2+1)x=0

Please solve it for me!! Please...Maths  Reiny, Thursday, April 4, 2013 at 7:48am
6log(x^2+1)x=0
6 log(x^2 + 1) = x
log(x^2 + 1) = x/6
x^2 + 1 = e^(x/6)
wow ....
try Wolfram, since there is no "nice" way to solve this
http://www.wolframalpha.com/input/?i=x%5E2+%2B+1+%3D+e%5E%28x%2F6%29
It says: x = appr 0 or x = appr .169 or x = appr 45.93
testing:
if x = 0
LS = 6ln(1)  0 = 0 = RS > x = 0
if x = .169
LS = 6ln(1.028561)  .169
= .000035 and RS = 0 >not bad, x = appr .169
if x = 45.93
LS = 6ln(2110.5649)  45.93
= .0017.. close to zero > x = appr 45.93
all three answers work!!!!
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