Posted by **Seth** on Thursday, April 4, 2013 at 1:26am.

Solve for the value of x: 6log(x^2+1)-x=0

- Please solve it for me!! Please...Maths -
**Reiny**, Thursday, April 4, 2013 at 7:48am
6log(x^2+1)-x=0

6 log(x^2 + 1) = x

log(x^2 + 1) = x/6

x^2 + 1 = e^(x/6)

wow ....

try Wolfram, since there is no "nice" way to solve this

http://www.wolframalpha.com/input/?i=x%5E2+%2B+1+%3D+e%5E%28x%2F6%29

It says: x = appr 0 or x = appr .169 or x = appr 45.93

testing:

if x = 0

LS = 6ln(1) - 0 = 0 = RS ----> x = 0

if x = .169

LS = 6ln(1.028561) - .169

= -.000035 and RS = 0 ---->not bad, x = appr .169

if x = 45.93

LS = 6ln(2110.5649) - 45.93

= -.0017.. close to zero -----> x = appr 45.93

all three answers work!!!!

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