Posted by kathryn on Wednesday, April 3, 2013 at 8:37pm.
How would I solve from this point?
- math check my answers - kathryn, Wednesday, April 3, 2013 at 8:50pm
- math check my answers - PsyDAG, Wednesday, April 3, 2013 at 10:40pm
1. 2(x+3)^2-6x+5 = 0
(x+3)^2 = x^2 + 6x + 9
2x^2 +12x + 18 - 6x +5 = 0
2x^2 + 6x +17 = 0
Unless you have a typo, I don't agree with your answer.
2. 3x^2 - 6x + 5 = 2x + 2 - 10
3x^2 - 8x + 2 = 0
Remember that, if you subtract/add from one side, you have to do the same thing to the other side of the equation.
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